DateDiff
The DateDiff function will calculate the number of units
of time difference between the two date parameters. This means
you can measure the difference in time however you like. Hours,
Minutes, Seconds.. etc.
dDate
dDate = DateAdd("d", 1, Now())
Response.Write "Hours Difference = " & DateDiff("h", dDate, Now())
| Unit |
Meaning |
| d |
Day |
| m |
Month |
| yyyy |
Year |
| q |
Quarter |
| w |
Weekday |
| ww |
Week of Year |
| h |
Hour |
| n |
Minute |
| s |
Second |
|
 |
|
